If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4x^2+2x=112
We move all terms to the left:
4x^2+2x-(112)=0
a = 4; b = 2; c = -112;
Δ = b2-4ac
Δ = 22-4·4·(-112)
Δ = 1796
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1796}=\sqrt{4*449}=\sqrt{4}*\sqrt{449}=2\sqrt{449}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{449}}{2*4}=\frac{-2-2\sqrt{449}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{449}}{2*4}=\frac{-2+2\sqrt{449}}{8} $
| -5x-2=x-2-6x | | 6x3+x=32 | | -8x-14=0 | | 9x-(-7)=16x | | n2-6n+13=0 | | (x+(3x+2))*x=112 | | x*7-36=118 | | x+(3x+2)*x=112 | | t/6+7=9 | | 24-5x=12+x | | 12y^2+8y-20=0 | | 34-5(p-2)=5 | | x+2=6x−18 | | 13x+13=-31-8x | | 14-2c^2-3c=0 | | 7+4(t-3)=25 | | F(x)=3x^2+4x-6 | | 7.3n=58.4 | | 10y+8=3 | | 20s+33=93 | | 3n+4=29 | | 5^(x+1)+4/(5^x)-21=0 | | 13=a-7.4 | | (8x-3)(2+x)+(8x-3)(x-7)=0 | | 3k2=8k+8 | | -31+x=14 | | 100-20x+x^2=4x^2 | | 3(2x-4)=2(x-10) | | 7÷x-6=3 | | 10x^2-7=13 | | 42=3/2w | | 5x+40=2x-15x-1 |